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5x^2-4x-11.25=0
a = 5; b = -4; c = -11.25;
Δ = b2-4ac
Δ = -42-4·5·(-11.25)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{241}}{2*5}=\frac{4-\sqrt{241}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{241}}{2*5}=\frac{4+\sqrt{241}}{10} $
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